Calculate the number of covalent bonds in $H_2O$,$NH_3$,and $CCl_4$. Why?

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(N/A) The number of covalent bonds in a molecule is determined by the number of shared electron pairs between atoms to achieve a stable octet or duplet configuration.
$1$. In $H_2O$: The central oxygen atom shares two electrons with two hydrogen atoms,forming $2$ $O-H$ covalent bonds.
$2$. In $NH_3$: The central nitrogen atom shares three electrons with three hydrogen atoms,forming $3$ $N-H$ covalent bonds.
$3$. In $CCl_4$: The central carbon atom shares four electrons with four chlorine atoms,forming $4$ $C-Cl$ covalent bonds.
The number of bonds is determined by the valency of the central atom and the requirement to complete the valence shell of each atom involved in the bonding.

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The table shown below gives the bond dissociation energies $E_{diss}$ for single covalent bonds of carbon $C$ atoms with elements $A, B, C$ and $D.$ Which element has the smallest atoms?
$Bond$ $E_{diss} (kJ \ mol^{-1})$
$C-A$ $240$
$C-B$ $328$
$C-C$ $276$
$C-D$ $485$

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